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Calculate The ratio of [Ag(NH(3))(2)]^...

Calculate
The ratio of `[Ag(NH_(3))_(2)]^(+)and[Ag^(+)]` in 0.1 M `NH_(3)` solution.

Text Solution

Verified by Experts

The equilibrium set up is
`Ag^(+)+2NH_(3)overset(K_(f))()[Ag(NH_(3))_(2)]^(+)`
`therefore` Stability constant, `K_(f)=([Ag(NH_(3))_(2)]^(+))/([Ag^(+)][NH_(3)]^(2))`
`=1.7xx10^(7)`, (given)
or `([Ag(NH_(3))_(2)]^(+))/([Ag^(+)])=1.7xx10^(7)xx[NH_(3)]^(2)`
`=1.7xx10^(7)xx(0.1)^(2)=1.7xx10^(5)`
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