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Calculate The ratio of [Ag(NH(3))(2)]^...

Calculate
The ratio of `[Ag(NH_(3))_(2)]^(+)and[Ag^(+)]` in 0.1 M `NH_(3)` solution.

Text Solution

Verified by Experts

The equilibrium set up is
`Ag^(+)+2NH_(3)overset(K_(f))()[Ag(NH_(3))_(2)]^(+)`
`therefore` Stability constant, `K_(f)=([Ag(NH_(3))_(2)]^(+))/([Ag^(+)][NH_(3)]^(2))`
`=1.7xx10^(7)`, (given)
or `([Ag(NH_(3))_(2)]^(+))/([Ag^(+)])=1.7xx10^(7)xx[NH_(3)]^(2)`
`=1.7xx10^(7)xx(0.1)^(2)=1.7xx10^(5)`
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Knowledge Check

  • [Cr(NH_(3))_(6)]^3 ion is :

    A
    Paramagnetic
    B
    Diamagnetic
    C
    Square planar
    D
    None

  • The IUPAC name of [Cr(NH_(3))_(4)Cl_(2)]NO_(3) is:

    A
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    B
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    C
    dichloro tetramine chromium (III) nitrate
    D
    tetra amino dichloro chromium (II) nitrate

  • The shape of the complex Ag(NH_3)_2^+ is:

    A
    Octahedral
    B
    Square planar
    C
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    D
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