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Assertion : A solution which is 10^(-3) ...

Assertion : A solution which is `10^(-3)` M each in `Mn^(2+), Fe^(2+), Zn^(2+) and Hg^(2+)` is treated with an aq. Solution of `H_(2)S` in which the `S^(2-)` concentration is `10^(-16)` M. The metal sulphide which precipitates out first is HgS. (The Ksp values of MnS, FeS, ZnS and HgS are respectively `10^(-15), 10^(-23), 10^(-20) and 10^(-54)M^(2)`)
Reason : The metal sulphide whose `K_(sp)` first gets exceeded, will precipitate out first.

A

Both assertion and reason are correct and reason is the correct explanation of assertion

B

Both assertion and reason are correct and reason is not the correction explanation of assertion

C

Assertion is true, reason is false

D

Assertion is false, reason is true

Text Solution

Verified by Experts

The correct Answer is:
A
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Knowledge Check

  • The number of molecules in 32 g of oxygen is 3.2xx10^(16) , 6.0xx10^(23) , 3.2xx10^(23) , 6.0xx10^(10)

    A
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    B
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    `3.2 times 10^(-8)`
    B
    `2.56 times 10^(-7)`
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  • A light rod with uniform cross-section of 10^(-4)m^(2) is shown in the figure. The rod consists of three different materials whose lengths are 0.1 m, 0.2 mand 0.15 m respectively and whose Young's moduli are 2.5 xx 10^(10) N//m^(2), 4xx10^(10) N//m^(2) and 1 xx 10^(10) N//m^(2) respectively. The displacement of point B will be

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