Home
Class 12
CHEMISTRY
Calculate the potential for half-cell co...

Calculate the potential for half-cell containing 0.10 M `K_(2) Cr_(2) O_(7) ` (aq), 0.20 M `Cr^(3+) (aq)` and `1.0 xx 10^(-4) MH^(+) ( aq)`. The half- cell reaction is
`Cr_(2) O_(7)^(2-) ( aq) + 14H^(+) ( aq) + 6e^(-)rarr 2Cr^(3+) (aq) + 7 H_(2) O ( l )` and the standard electrode potential is given as `E^(@) = 1.33 V`.

Text Solution

Verified by Experts

The correct Answer is:
0.7823V
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise QUESTIONS FOR ASSESSMENT ( PART III ELECTROLCHEMICAL CELLS AND SERIES , NERNST EQUATIONS, BATTERIES AND CORROSION ) ( LONG ANSWER TYPE QUESTIONS) |2 Videos

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise ODISHA BUREAU.S TEXTBOOK SOLUTIONS (MULTIPLE CHOICE TYPE QUESTIONS)|16 Videos

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise QUESTIONS FOR ASSESSMENT ( PART III ELECTROLCHEMICAL CELLS AND SERIES , NERNST EQUATIONS, BATTERIES AND CORROSION ) ( SHORT ANSWER TYPE I QUESTIONS) |6 Videos

  • D-BLOCK ELEMENTS

    ARIHANT PUBLICATION|Exercise Chapter practice (Long answer type questions)|2 Videos

  • ELEMENTS : NITROGEN FAMILY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( Long Answer Type Questions ) |11 Videos

Similar Questions

Explore conceptually related problems

Consider the reaction, Cr_(2) O_(7) ^(2-) + 14 H^(+) + 6e^(-) rarr 2Cr^(3+) + 7 H_(2) O What is the quantity of electricity in coulombs needed to reduce 1 mole of Cr_(2)O_(7)^(2-) ?

Complete the following chemical equations : Cr_(2) O_(7)^(2-) + 6 Fe^(2+) + 14 H^(+) to

The charge for the reduction of 1 mole of Cr_2O_7^(2-) ions to Cr^(3+) is :

K_(2)Cr_(2)O_(7)//H^(+) changes to green by

Balance the equation : Cr_2O_7^(2-) +H^+ + S^2 rarrCr^3 + S + H_2O

In the reaction , Cr_2O_7^(2-) + 14H^+ +6I → 2Cr^(3+) + 7H_2 O +3I_(2 which element is reduced ?

Balance the equation : Cr_3O_7^(2-) + H^+ + I^- rarr Cr^3 + I2 +H_2O

Describe the process of preparation of K_(2)Cr_(2)O_(7) and KMnO_(4) .