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Calculate the potential for half-cell co...

Calculate the potential for half-cell containing 0.10 M `K_(2) Cr_(2) O_(7) ` (aq), 0.20 M `Cr^(3+) (aq)` and `1.0 xx 10^(-4) MH^(+) ( aq)`. The half- cell reaction is
`Cr_(2) O_(7)^(2-) ( aq) + 14H^(+) ( aq) + 6e^(-)rarr 2Cr^(3+) (aq) + 7 H_(2) O ( l )` and the standard electrode potential is given as `E^(@) = 1.33 V`.

Text Solution

Verified by Experts

The correct Answer is:
0.7823V
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Consider the reaction, Cr_(2) O_(7) ^(2-) + 14 H^(+) + 6e^(-) rarr 2Cr^(3+) + 7 H_(2) O What is the quantity of electricity in coulombs needed to reduce 1 mole of Cr_(2)O_(7)^(2-) ?

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Knowledge Check

  • NaOH(aq) + HCl(aq) to Na^(+)Cl^(-(aq)) + H_(2)O(l) is a reaction .

    A
    precipitation reaction
    B
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    C
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  • The charge for the reduction of 1 mole of Cr_2O_7^(2-) ions to Cr^(3+) is :

    A
    96500C
    B
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    C
    `3xx96500C`
    D
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