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Line segment joining (5, 0) and (10 cost...

Line segment joining `(5, 0)` and `(10 costheta,10 sintheta)` is divided by a point P in ratio `2 : 3` If `theta` varies then locus of P is a ; A) Pair of straight lines B) Straight line C) Circle D) Parabola

Text Solution

Verified by Experts

Let point P be `(h,k)`

Here,`h=(2(10costheta)+3(5))/(2+3)=4 sin theta+ 3`
`k=(2(10sintheta)+3(0))/(2+3)=4 sin theta`
`therefore (h-3)^2+k^2=16`
Therefore, locus of `P(h,k)` is `(x-3)^2+y^2=16`.
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Knowledge Check

  • The line segment joining the points (1,2) and (-2, 1) is divided by the line 3x+4y=7 in the ratio

    A
    `3:4`
    B
    `4:3`
    C
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  • The ratio in which the line segment joining the points (1, 2, 3) and (-3, 4, -5) is divided by the xy -plane is -

    A
    `3:5`
    B
    `4:3`
    C
    `-3:5`
    D
    `5:2`
  • Let 2x-3y=0 be a given line and P(sintheta, 0) and Q(0, costheta) be the two points. Then P and Q lie on the same side of the given line, if theta lies in

    A
    `1^(st) or 4^(th)` quadrant
    B
    `2^(nd) or 4^(th)` quadrant
    C
    `1^(st) or 2^(nd)` quadrant
    D
    `2^(nd) or 3^(rd)` quadrant
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