Home
Class 7
MATHS
Find the product of 7/2s^2t\ a n d\ s+td...

Find the product of `7/2s^2t\ a n d\ s+tdot` Verify the result for `s=1/2a n d\ t=5.`

Text Solution

Verified by Experts

The correct Answer is:
`= (495)/(8)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ALGEBRAIC EXPRESSIONS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (INTEGER/NUMERICAL VALUE TYPE)|10 Videos
  • ALGEBRAIC EXPRESSIONS

    MTG IIT JEE FOUNDATION|Exercise OLYMPIAD/HOTS CORNER|10 Videos
  • ALGEBRAIC EXPRESSIONS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (SHORT ANSWER TYPE)|13 Videos
  • COMPARING QUANTITIES

    MTG IIT JEE FOUNDATION|Exercise Olympaid/HOTS Corner|20 Videos

Similar Questions

Explore conceptually related problems

Find the product of (7)/(2)s^(2)t and s+t .Verify the result for s=(1)/(2) and t=5

Find the product s(s^(2) - st) and find its value s= 2 and t = 3.

Knowledge Check

  • In a harmonic progression t_(1), t_(2), t_(3),……………., it is given that t_(5)=20 and t_(6)=50 . If S_(n) denotes the sum of first n terms of this, then the value of n for which S_(n) is maximum is

    A
    6
    B
    7
    C
    9
    D
    10
  • Similar Questions

    Explore conceptually related problems

    In an arithmetic progression, if S_n = n(5+3n) and t_n = 32, then the value of n is [Note : S_n and t_n denote the sum of first n terms and nth term of arithmetic progression respectively.] (A)4(B)5(C)6(D)7

    Let f(x)=x^3+3x+2a n dg(x) be the inverse of it. Then the area bounded by g(x) , the x-axis, and the ordinate at x=-2a n dx=6 is 1/4s qdotu n i t s (b) 4/3s qdotu n i t s 5/4s qdotu n i t s (d) 7/3s qdotu n i t s

    Let T_(r) and S_(r) be the rth term and sum up to rth term of a series,respectively.If for an odd number n,S_(n)=n and T_(n)=(T_(n)-1)/(n^(2)), then T_(m)(m being even) is (2)/(1+m^(2)) b.(2m^(2))/(1+m^(2)) c.((m+1)^(2))/(2+(m+1)^(2))d(2(m+1)^(2))/(1+(m+1)^(2))

    Charge through a cross-section of a conductor is given by Q = 5t^(2) - 2t coulomb . Find the average current through the conductor in the interval t_(1) = 2s to t_(2) = 4s (1) 14s (2) 28 A (3) 56A (4) 7A

    The area of the region whose boundaries are defined by the curves y=2cosx , y=3tanx ,a n dt h ey-a xi si s 1+31n(2/(sqrt(3)))s qdotu n i t s 1+3/2 1n3-31n2s qdotu n i t s 1+3/2 1n3-1n2s qdotu n i t s 1n3-1n2s qdotu n i t s

    If sum of n termsof a sequende is S_n then its nth term t_n=S_n-S_(n-1) . This relation is vale for all ngt-1 provided S_0= 0. But if S_!=0 , then the relation is valid ony for nge2 and in hat cast t_1 can be obtained by the relation t_1=S_1. Also if nth term of a sequence t_1=S_n-S_(n-1) then sum of n term of the sequence can be obtained by putting n=1,2,3,.n and adding them. Thus sum_(n=1)^n t_n=S_n-S_0. if S_0=0, then sum_(n=1)^n t_n=S_n. On the basis of above information answer thefollowing questions:If nth term of a sequence is n/(1+n^2+n^4) then the sum of its first n terms is (A) (n^2+n)/(1+n+n^2) (B) (n^2-n)/(1+n+n^2) (C) (n^2+n)/(1-n+n^2) (D) (n^2+n)/(2(1+n+n^2)

    A tangent having slope of -4/3 to the ellipse (x^2)/(18)+(y^2)/(32)=1 intersects the major and minor axes at point Aa n dB , respectively. If C is the center of the ellipse, then the area of triangle A B C is 12s qdotu n i t s (b) 24s qdotu n i t s 36s qdotu n i t s (d) 48s qdotu n i t s