Find the value of expression `(4x-3y)(4x+3y+5)-4x+12y` when x= 2 and y= 3.

Answer

To find the value of the expression \((4x - 3y)(4x + 3y + 5) - 4x + 12y\) when \(x = 2\) and \(y = 3\), we will substitute the values of \(x\) and \(y\) into the expression step by step.

### Step-by-Step Solution:

1. **Substitute the values of \(x\) and \(y\)**:
\[ x = 2, \quad y = 3 \]

2. **Calculate \(4x\) and \(3y\)**:
\[ 4x = 4 \times 2 = 8 \]
\[ 3y = 3 \times 3 = 9 \]

3. **Substitute \(4x\) and \(3y\) into the expression**:
The expression becomes:
\[ (8 - 9)(8 + 9 + 5) - 8 + 36 \]

4. **Simplify the first bracket**:
\[ 8 - 9 = -1 \]

5. **Simplify the second bracket**:
\[ 8 + 9 + 5 = 22 \]

6. **Now substitute back into the expression**:
The expression now looks like:
\[ (-1)(22) - 8 + 36 \]

7. **Calculate \((-1)(22)\)**:
\[ -1 \times 22 = -22 \]

8. **Combine all parts of the expression**:
\[ -22 - 8 + 36 \]

9. **Calculate \(-22 - 8\)**:
\[ -22 - 8 = -30 \]

10. **Finally, calculate \(-30 + 36\)**:
\[ -30 + 36 = 6 \]

### Final Answer:
The value of the expression \((4x - 3y)(4x + 3y + 5) - 4x + 12y\) when \(x = 2\) and \(y = 3\) is \(6\).