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The equation of the locus of points equi...

The equation of the locus of points equidistant from `(-1-1)` and `(4,2)` is

A

`3x-5y-7=0`

B

`5x+3y-9=0`

C

`4x+3y+2=0`

D

`x-3y+5=0`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • The point on the axis of y which is equidistant from (1, -2) and (3, 4) is

    A
    (0, 4)
    B
    (0, 5)
    C
    (5, 0)
    D
    none of these

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