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The recoil energy of a hydrogen atom aft...

The recoil energy of a hydrogen atom after it emits a photon in going from n = 5 state to n = 1 state is (M = Mass of H atom, R = Rydberg's constant, h = Planck's constant)

A

`10^(-4) m//s`

B

`2 xx 10^(-2) m//s`

C

`4.2 m//s`

D

`3.8 xx 10^(-2) m//s`

Text Solution

Verified by Experts

The correct Answer is:
C
(a) `DeltaE=13.6 (1/1^(2)-1/5^(2))=(hc)/lambda+1/2 mv^(2)`
(b) `0=mv-h/lambda`
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