Statement-1 : `CH_(4)` and `CH_(2)F_(2)` are having regular tetrahedron geometry.
Statements: 2 Both are having same hybridization.

Options

A. Statement -1 is true, Statement-2 is true and statement-2 is correct explanation for statement -1.
B. Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1
C. Statement-1 is true, statement-2 is false
D. Statement-1 is false, statement-2 is true.

Answer

To solve the question, we need to analyze the two statements regarding the compounds CH₄ (methane) and CH₂F₂ (difluoromethane).

### Step 1: Determine the Geometry of CH₄
1. **Identify the central atom**: In CH₄, the central atom is carbon (C).
2. **Count the valence electrons**: Carbon is in group 14, so it has 4 valence electrons.
3. **Count the attached atoms**: There are 4 hydrogen atoms attached to carbon.
4. **Determine hybridization**:
- Use the formula:
\[ \text{Number of hybrid orbitals} = \frac{1}{2} \left( \text{Valence electrons} + \text{Monovalent atoms} - \text{Charge on cation} + \text{Charge on anion} \right) \]
- For CH₄:
\[ \text{Number of hybrid orbitals} = \frac{1}{2} \left( 4 + 4 - 0 + 0 \right) = \frac{1}{2} \times 8 = 4 \]
- Since there are 4 hybrid orbitals, the hybridization is sp³.
5. **Determine geometry**: With 4 bond pairs and no lone pairs, CH₄ has a tetrahedral geometry.

### Step 2: Determine the Geometry of CH₂F₂
1. **Identify the central atom**: In CH₂F₂, the central atom is also carbon (C).
2. **Count the valence electrons**: Carbon has 4 valence electrons.
3. **Count the attached atoms**: There are 2 hydrogen atoms and 2 fluorine atoms attached to carbon.
4. **Determine hybridization**:
- For CH₂F₂:
\[ \text{Number of hybrid orbitals} = \frac{1}{2} \left( 4 + 4 - 0 + 0 \right) = \frac{1}{2} \times 8 = 4 \]
- The hybridization is also sp³.
5. **Determine geometry**: With 4 bond pairs and no lone pairs, CH₂F₂ also has a tetrahedral geometry.

### Step 3: Conclusion
- **Statement 1**: Both CH₄ and CH₂F₂ have tetrahedral geometry. This is true.
- **Statement 2**: Both compounds have the same hybridization (sp³). This is also true.

Thus, both statements are correct, and statement 2 provides a correct explanation for statement 1.

### Final Answer:
- **Statement 1** is true.
- **Statement 2** is true, and it is a correct explanation for statement 1.

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