Which of following pair of species is having different hybridisation but same shape.

Options

A. `BeCl_(2)` and `CO_(2)`
B. `CO_(2)` and `SO_(2)`
C. `SO_(2)` and `I_(3)^(+)`
D. `ICl_(2)^(-)` and `BeH_(2)`

Answer

To determine which pair of species has different hybridization but the same shape, we will analyze each option provided in the question step by step.

### Step 1: Analyze Option A (BeCl2 and CO2)
1. **BeCl2**:
- Beryllium (Be) has 2 valence electrons and forms 2 sigma bonds with 2 chlorine (Cl) atoms.
- The shape of BeCl2 is linear.
- Hybridization: sp.

2. **CO2**:
- Carbon (C) has 4 valence electrons and forms 2 double bonds (2 sigma and 2 pi bonds) with 2 oxygen (O) atoms.
- The shape of CO2 is also linear.
- Hybridization: sp.

**Conclusion for Option A**: Both BeCl2 and CO2 have the same shape (linear) and the same hybridization (sp). This option does not satisfy the condition.

### Step 2: Analyze Option B (SO2 and CO2)
1. **SO2**:
- Sulfur (S) has 6 valence electrons and forms 2 sigma bonds with 2 oxygen atoms, and has 1 lone pair.
- The shape of SO2 is bent.
- Hybridization: sp2.

2. **CO2**:
- As analyzed before, CO2 has a linear shape and sp hybridization.

**Conclusion for Option B**: SO2 has a bent shape and sp2 hybridization, while CO2 has a linear shape and sp hybridization. This option does not satisfy the condition.

### Step 3: Analyze Option C (SO2 and I3^-)
1. **SO2**:
- As analyzed before, SO2 has a bent shape and sp2 hybridization.

2. **I3^-**:
- Iodine (I) has 7 valence electrons, and with a negative charge, it has 8 electrons. It forms 2 sigma bonds with 2 iodine atoms and has 3 lone pairs.
- The shape of I3^- is linear (due to the arrangement of the lone pairs).
- Hybridization: sp3.

**Conclusion for Option C**: SO2 has a bent shape and sp2 hybridization, while I3^- has a linear shape and sp3 hybridization. This option does not satisfy the condition.

### Step 4: Analyze Option D (ICl2^- and BeH2)
1. **ICl2^-**:
- Iodine (I) has 7 valence electrons, and with a negative charge, it has 8 electrons. It forms 2 sigma bonds with 2 chlorine atoms and has 3 lone pairs.
- The geometry is trigonal bipyramidal, but the shape is linear due to the arrangement of the lone pairs.
- Hybridization: sp3d.

2. **BeH2**:
- Beryllium (Be) has 2 valence electrons and forms 2 sigma bonds with 2 hydrogen (H) atoms.
- The shape of BeH2 is linear.
- Hybridization: sp.

**Conclusion for Option D**: ICl2^- has a linear shape and sp3d hybridization, while BeH2 has a linear shape and sp hybridization. This option satisfies the condition of different hybridization but the same shape.

### Final Conclusion
The pairs of species that have different hybridization but the same shape are found in **Option D (ICl2^- and BeH2)**.

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