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A particle is thrown over a triangle from one end of a horizontal base and after grazing the vertex falls on the other end of the base. If `alpha and beta` be the base angles and `theta` the angle of projection, prove that `tan theta = tan alpha + tan beta` .

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From triangle `y=x tan alpha`
`y=(R-x)tan beta`
` because y=x tan theta[1-(x)/(R)]rArr tan theta=(yR)/(x(R-x)) therefore tan theta=tan alpha+tan beta` (H.P)
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