Home
Class 11
PHYSICS
The dimensions of (1)/(2)epsilon(0)E^(2)...

The dimensions of `(1)/(2)epsilon_(0)E^(2)`, where `epsilon_(0)` is permittivity of free space and E is electric field, are

A

`[MLT^(-1)]`

B

`[ML^(2)T^(-2)]`

C

`[ML^(-1)T^(-2)] `

D

`[ML^(2)T^(-1)]`

Text Solution

Verified by Experts

The correct Answer is:
C

`(1)/(2) in_0 E^(2)` = Energy density = `("Energy")/("Volume")= [M^(1)L^(-1)T^(-2)]`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise EXERCISE-II AIPMT (MAINS) 2010|1 Videos
  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise EXERCISE-II AIIMS 2010|1 Videos
  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise EXERCISE-II AIPMT 2009|1 Videos
  • MISCELLANEOUS

    ALLEN|Exercise Question|1 Videos
  • SEMICONDUCTORS

    ALLEN|Exercise Part-3(Exercise-4)|51 Videos

Similar Questions

Explore conceptually related problems

The dimension of ((1)/(2))epsilon_(0)E^(2) ( epsilon_(0) : permittivity of free space, E electric field

The dimension of ((1)/(2))epsilon_(0)E^(2) ( epsilon_(0) : permittivity of free space, E electric field

The dimensions of 1/2 epsilon_(0)E^(2) (epsilon_(0)= permittivity of free space, E= electric field) is

The dimensions of (mu_(0)epsilon_(0))^(-1//2) are

The dimensions of epsilon_(0)mu_(0) are

A wire of length L= 20 cm is bent into a semicircular arc and the two equal halves of the arc are uniformly charged with charges +Q and -Q as shown in the figure. The magnitude of the charge on each half is |Q| =10^(3) epsilon_(0) , where epsilon_(0) is the permittivity of free the space. The net electric field at the center O is

The dimensions of 1/2 in_(0) E^(2) ( in_(0) : permittivity of free space, E: electric field) is-

The quantity X = (epsilon_(0)LV)/(t) where epsilon_(0) is the permittivity of free space, L is length, V is the potential difference and t is time. The dimensions of X are the same as that of

A quantity X is given by epsilon_(0) L(DeltaV)/(Deltat) , where epsilon_(0) is the permittivity of free space L is a length DeltaV is a potnetial difference and Delta is a time internval. The dimensional forumla to X is the same as that of

epsilon_(0)E^(2) has the dimensions of ( epsilon_(0)= permittivity of free space, E= electric field) Here k= Boltzmann consant T= absolute temperature R= universal gas constant.