The dimensional null formula of magnetic permeability is

Options

A. `MLT^(2)A^(-2)`
B. `ML^(-1)T^(-2)A^(-2)`
C. `ML^(-2)T^(-2)A^(2)`
D. `MLT^(-2)A^(-2)`

Answer

D

Explanation

Force per unit length between two parallel current carrying wires is given by `(F)/(l) = (mu_(0)I_(1)I_(2))/(2pid)`
`therefore [mu_0] = [(F)/(I^(2))] = [(MLT^(-2))/(A^(2))] = [MLT^(-2)A^(-2)]`