If the dimensions of a physical quantity...

If the dimensions of a physical quantity are given by `["M"^(a)"L"^(b)"T"^(c)]`, then the physical quantity will be

Force if a = 0, b = -1, c =-2

Pressure if a = 1, b =-1, c = -2

Velocity if a =1, b =0, c=-1

Acceleration if a = 1, b=1, c=-2

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The correct Answer is:

[Force ] = `[MLT^(-2)]`
[Pressure] = `[ML^(-1)^(-2)]`
[Velocity] = `[LT^(-1)]`
[Acceleration] = `[LT^(-2)]`

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The dimensional formula of physical quantity is [M^(a)L^(b)T^(c)] .Then that physical quantity is

surface tension if a=1,b=1,c=-2

force if a=1,b=1,c=2

angular frequency if a=0,b=0,c=-1

spring constant if a=1,b=-1,c=-2