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Two paricles of equal mass `m` go round a circle of radius R under the action of their mutual gravitional attraction. The speed of each particle is

A

`(1)/(2R)sqrt((1)/(Gm)`

B

`sqrt((Gm)/(2R))`

C

`(1)/(2)sqrt((Gm)/(R))`

D

`sqrt((4Gm)/(R))`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. The speed v of each particle is

    A
    `(1)/(2R ) sqrt(((1)/(Gm)))`
    B
    ` sqrt(((Gm)/(2R)))`
    C
    `(1)/(2)sqrt(((Gm)/(R )))`
    D
    `sqrt(((4Gm)/(R )))`

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