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AD is an altitude of an isosceles triang...

AD is an altitude of an isosceles triangle ABC in which AB = AC .
Show that ,
AD bisects BC

Answer

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AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that, (i) AD bisects BC (ii) AD bisects /_ A.

AD is an altitude of an isosceles triangle ABC in which AB = AC . Show that , AD bisects angle A .

Knowledge Check

  • Masses each 1 kg are placed at the verticies of an isosceles triangle ABC in which AC = BC = 5cm and AB = 8 cm. The distance of centre of mass of the system from the vertex C is

    A
    2 cm
    B
    1 cm
    C
    1.5 cm
    D
    3 cm

  • Masses each 1kg are placed at the verticies of an isosceles triangle ABC in which AC=BC=5cm and AB=8cm. The distance of centre of mass of the system from the vertex C is

    A
    `2cm`
    B
    `1cm`
    C
    `1.5cm`
    D
    `3cm`

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