AD is an altitude of an isosceles triangle ABC in which AB = AC .
Show that ,
AD bisects BC

AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that, (i) AD bisects BC (ii) AD bisects /_ A.

AD is an altitude of an isosceles triangle ABC in which AB = AC . Show that , AD bisects angle A .

triangleABC is an isosceles triangle in which AB = AC. Show angleB=angleC (Hint : Draw APbotBC) (Using RHS congruence rule)

Masses each 1 kg are placed at the verticies of an isosceles triangle ABC in which AC = BC = 5cm and AB = 8 cm. The distance of centre of mass of the system from the vertex C is

ABC is an isosceles triangle in which AB = AC. AD bisects exterior angle QAC and CD "||" BA as shown in the figure. Show that (i) angleDAC = angleBCA (ii) ABCD is a parallelogram

DeltaABC is an isosceles triangle in which AB = AC. Side BA is produced to D such that AD = AB (see figure). Show that /_BCD is a right angle.

In an isosceles triangle ABC with AB = AC, D and E are points on BC such that BE = CD (see figure) Show that AD = AE

/_\ABC is an isosceles triangle with AB=AC. Draw AP _|_ BC to show that /_B=/_C

ABC is an isosceles triangle right angled at C. Prove that AB^2=2AC^2 .