If two deuterons are fused to form one Helium than what will be amount of energy released, if the binding energy of deuteron is 2.2MeV and that of Helium is 28MeV

Options

A. 25.8MeV
B. 23.6MeV
C. 19.2MeV
D. 30.2MeV

Explanation

To solve the problem of calculating the energy released when two deuterons fuse to form one helium nucleus, we can follow these steps:

### Step 1: Understand the binding energies
- The binding energy of a deuteron (D) is given as 2.2 MeV.
- The binding energy of a helium nucleus (He) is given as 28 MeV.

### Step 2: Calculate the total binding energy of the two deuterons
- Since we have two deuterons, we need to calculate their total binding energy:
\[ \text{Total binding energy of 2 deuterons} = 2 \times \text{Binding energy of deuteron} = 2 \times 2.2 \text{ MeV} = 4.4 \text{ MeV} \]

### Step 3: Calculate the energy released during fusion
- The energy released during the fusion process can be calculated by finding the difference between the binding energy of helium and the total binding energy of the two deuterons:
\[ \text{Energy released} = \text{Binding energy of helium} - \text{Total binding energy of 2 deuterons} \]
\[ \text{Energy released} = 28 \text{ MeV} - 4.4 \text{ MeV} = 23.6 \text{ MeV} \]

### Final Answer
- The amount of energy released when two deuterons fuse to form one helium nucleus is **23.6 MeV**.

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