Find the inverse ratio of maximum to minimum wavelength in Lyman series.

Options

A. `9:5`
B. `4:3`
C. `36:5`
D. `4:1`

Answer

B

Explanation

For maximum wavelenth `lamda_("max")`
`n_(1)=1,n_(2)=2`
`1/(lamda_(max))=R(1/((1)^(2))-1/((2)^(2)))`
`lamda_(max)=4/(3pi)`
For minimum wavelength `lamda_(min)`
`n_(1)=1,n_(2)=oo`
`1/(lamda_(min))=R`
`lamda_(min)=1/R`
`(lamda_(max))/(lamda_(min))=4/(3R1/R)=(4/3)`