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Find the inverse ratio of maximum to min...

Find the inverse ratio of maximum to minimum wavelength in Lyman series.

A

`9:5`

B

`4:3`

C

`36:5`

D

`4:1`

Text Solution

Verified by Experts

The correct Answer is:
B
For maximum wavelenth `lamda_("max")`
`n_(1)=1,n_(2)=2`
`1/(lamda_(max))=R(1/((1)^(2))-1/((2)^(2)))`
`lamda_(max)=4/(3pi)`
For minimum wavelength `lamda_(min)`
`n_(1)=1,n_(2)=oo`
`1/(lamda_(min))=R`
`lamda_(min)=1/R`
`(lamda_(max))/(lamda_(min))=4/(3R1/R)=(4/3)`
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Knowledge Check

  • The ratio of minimum to maximum wavelength in Balmer series is

    A
    `5 : 9`
    B
    `5 : 36`
    C
    `1 : 4`
    D
    `3 : 4`

  • The maximum wavelength of Lyman series is

    A
    `C/R`
    B
    `1/R^2`
    C
    `(4)/(3R)`
    D
    `(1)/(CR)`

  • The wavelength of Lyman series is

    A
    `(4)/(3 xx 10967) cm`
    B
    `(3)/(4 xx 10967) cm`1
    C
    `(4 xx 10967)/(3) cm`
    D
    `(3)/(4) xx 109767 cm`

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    The ratio of minimum wavelengths of Lyman and Balmer series will be

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