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A person travels along a straight road f...

A person travels along a straight road for half the distance with velocity `V_1` and the remaining half distance with velocity `V_2` the average velocity is given by

A

`v_1v_2`

B

`(v_2/v_1)^2`

C

`(v_1+v_2)/2`

D

`(2v_1v_2)/(v_1+v_2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the average velocity of a person who travels half the distance with velocity \( V_1 \) and the other half with velocity \( V_2 \), we can follow these steps: ### Step 1: Define Total Distance Let's assume the total distance traveled by the person is \( 2x \). This means the first half of the distance is \( x \) and the second half is also \( x \). ### Step 2: Calculate Total Displacement The total displacement for the journey is equal to the total distance traveled, which is: \[ \text{Total Displacement} = 2x \] ### Step 3: Calculate Total Time Taken The total time taken to travel the distance can be calculated by adding the time taken for each half of the journey. 1. For the first half (distance \( x \) at velocity \( V_1 \)): \[ \text{Time}_1 = \frac{x}{V_1} \] 2. For the second half (distance \( x \) at velocity \( V_2 \)): \[ \text{Time}_2 = \frac{x}{V_2} \] Now, the total time taken \( T \) is: \[ \text{Total Time} = \text{Time}_1 + \text{Time}_2 = \frac{x}{V_1} + \frac{x}{V_2} \] ### Step 4: Simplify Total Time We can factor out \( x \) from the total time: \[ \text{Total Time} = x \left( \frac{1}{V_1} + \frac{1}{V_2} \right) \] ### Step 5: Calculate Average Velocity The average velocity \( V_{\text{avg}} \) is given by the formula: \[ V_{\text{avg}} = \frac{\text{Total Displacement}}{\text{Total Time}} \] Substituting the values we found: \[ V_{\text{avg}} = \frac{2x}{x \left( \frac{1}{V_1} + \frac{1}{V_2} \right)} \] ### Step 6: Cancel \( x \) and Simplify Cancelling \( x \) from the numerator and denominator: \[ V_{\text{avg}} = \frac{2}{\frac{1}{V_1} + \frac{1}{V_2}} \] ### Step 7: Further Simplification To simplify this expression, we can find a common denominator: \[ V_{\text{avg}} = \frac{2V_1V_2}{V_1 + V_2} \] ### Final Answer Thus, the average velocity of the person is: \[ V_{\text{avg}} = \frac{2V_1V_2}{V_1 + V_2} \]
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Knowledge Check

  • A man runs along the straight road for half the distance with velocity v_(1) and the remaining half distance with velocity v_(2) . Then the average velocity is given by

    A
    `v_(1)v_(2)`
    B
    `v_(2)^(2)//v_(1)^(2)`
    C
    `(v_(1) + v_(2))//2`
    D
    `2v_(1)v_(2)//(v_(1) + v_(2))`
  • A person travels along a straight road for the first half with a velocity v_(1) and the second half time with a velocity v_(2) . Then the mean velocity vecv is given by

    A
    `barv = (v_(1) + v_(2))/(2)`
    B
    `(2)/(v) = (1)/(v_(1)) + (1)/(v_(2))`
    C
    `barv = sqrt(v_(1)v_(2))`
    D
    `barv = sqrt((v_(2))/(v_(1)))`
  • A vehicle travels half the distance (L) with speed V_1 and the other half with speed V_2 , then its average speed is .

    A
    a. `v_1 + v_2/2`
    B
    b. `2v_1 + v_2/v_1 + v_2`
    C
    c. `2v_(1)v_2/(v_1 + v_2)`
    D
    d. `(v_1 + v_2)/v_(1)v_(2)`
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