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A ball of mass is thrown vertically up...

A ball of mass is thrown vertically upwards by applying a force by hand. If the hand moves while applying the force and the ball goes up to height further, find the magnitude of the force. (Take `g = 10 ms^(-2)`)

Text Solution

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`F=ma, F= m. (dv)/(dt)`
` 3x = m. (dv)/(dx).(dx)/(dt) , 3x=8. (dv)/(dt).v , 3x dx = 8v dv `
` 3int_(2)^(10)x dx = 8 int_0^(v) v dv , 3[(x^(2))/(2)]^(10)=8[(v^(2))/(2)]^(v) , 3[100-4]=8v^(2) , v^(2) = (3 xx 96)/(8) =36 , v=6 m//s`
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A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2 m while applying the force and the ball goes upto 2 m height further, find the magnitude of the force. (Consider g=10m//s^2 ).

A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2 m while applying the force and the ball goes upto 2 m height further, find the magnitude of the force. (Consider g=10m//s^2 ).

Knowledge Check

  • A ball of mass M is thrown vertically upwards. Another ball of mass 2M is thrown at an angle theta with the vertical. Both of them stay in air for the same period of time. The heights attained by the two are in the ratio

    A
    `1:2`
    B
    `2:1`
    C
    `1:1`
    D
    `1: cos theta`

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