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If Z=(A^2B^3)/(C^4), then the relative e...

If `Z=(A^2B^3)/(C^4)`, then the relative error in Z will be :

A

`(DeltaA)/A+(DeltaB)/B+(DeltaC)/C`

B

`(2DeltaA)/A+(3DeltaB)/B-(4DeltaC)/C`

C

`(2DeltaA)/A+(3DeltaB)/B+(4DeltaC)/C`

D

`(DeltaA)/A+(DeltaB)/B-(DeltaC)/C`

Text Solution

AI Generated Solution

The correct Answer is:
To find the relative error in \( Z = \frac{A^2 B^3}{C^4} \), we can use the formula for the propagation of errors in multiplication and division. ### Step-by-Step Solution: 1. **Identify the expression for Z**: \[ Z = \frac{A^2 B^3}{C^4} \] 2. **Rewrite Z**: We can express \( Z \) in terms of powers: \[ Z = A^2 B^3 C^{-4} \] 3. **Use the formula for relative error**: The relative error in a product or quotient can be calculated using the following formula: \[ \frac{\Delta Z}{Z} = \frac{\Delta A}{A} + \frac{\Delta B}{B} + \frac{\Delta C}{C} \] where \( \Delta A, \Delta B, \Delta C \) are the absolute errors in \( A, B, C \) respectively. 4. **Apply the powers to the relative errors**: Since \( Z \) involves powers of \( A, B, \) and \( C \), we need to multiply the relative errors by their respective powers: \[ \frac{\Delta Z}{Z} = 2 \frac{\Delta A}{A} + 3 \frac{\Delta B}{B} + 4 \frac{\Delta C}{C} \] 5. **Final expression for relative error in Z**: Thus, the relative error in \( Z \) is given by: \[ \frac{\Delta Z}{Z} = 2 \frac{\Delta A}{A} + 3 \frac{\Delta B}{B} + 4 \frac{\Delta C}{C} \] ### Conclusion: The relative error in \( Z \) is: \[ \frac{\Delta Z}{Z} = 2 \frac{\Delta A}{A} + 3 \frac{\Delta B}{B} + 4 \frac{\Delta C}{C} \]

To find the relative error in \( Z = \frac{A^2 B^3}{C^4} \), we can use the formula for the propagation of errors in multiplication and division. ### Step-by-Step Solution: 1. **Identify the expression for Z**: \[ Z = \frac{A^2 B^3}{C^4} \] ...
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If Z=(A^(4)B^(1/3))/(CD^(3/2)) ,than relative error in Z (Delta Z)/(Z) is equal to (a) ((Delta A)/(A))^(4)+((Delta B)/(B))^(1/3)-((Delta C)/(C))-((Delta D)/(D))^(3/2) (b) 4((Delta A)/(A))+((1)/(3))((Delta B)/(B))+((Delta C)/(C))+((3)/(2))((Delta D)/(D)) (c) 4((Delta A)/(A))+(1)/(3)((Delta B)/(B))-((Delta C)/(C))-((3)/(2))((Delta D)/(D)) (d) ((Delta A)/(A))^(4)+(1)/(3)((Delta B)/(B))+((Delta C)/(C))+(3)/(2)((Delta D)/(D))

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A physical quantity z depends of four obserbles a, b, c and d, as z = (a^2b^(2/3))/(sqrtc d^3) . The percentages of error in the measurement of a,b,c and d are 2%, 1.5%, 4% and 2.5% respectively. The peracentage of error in z is :

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If z_(1),z_(2),z_(3),z_(4) are the affixes of four point in the Argand plane,z is the affix of a point such that |z-z_(1)|=|z-z_(2)|=|z-z_(3)|=|z-z_(4)| ,then prove that z_(1),z_(2),z_(3),z_(4) are concyclic.

If A(z_1), B(z_2). C(z_3) are the vertices of an equilateral triangle ABC, then arg((z_2+z_2-2z_1)/(z_3-z_2))=pi/4 Reason(R): If /_B=alpha, then

Knowledge Check

  • z_(1),z_(2),z_(3) and z_(4) are the affixes of four points in the argand plane and z affix of a point such that |z-z_(1)|=|z-z_(2)|=|z-z_(3)| then =|z-z_(4)| , z_(1), z_(2), z_(3) and z_(4) are

    A
    concyclic
    B
    tices of parallelogram
    C
    vertices of rhombus
    D
    in a straight line
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