Home
Class 12
MATHS
The number of complex number z satisfyin...

The number of complex number z satisfying `abs(z-(4+3i))=2 and absz +abs(z-4) =6` is

A

0

B

1

C

2

D

3

Text Solution

Verified by Experts

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise MATHEMATICS (SECTION - B)|10 Videos
  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise MATHEMATICS |90 Videos
  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise Mathematics (Section A )|20 Videos
  • JEE MAINS 2023 JAN ACTUAL PAPER

    JEE MAINS PREVIOUS YEAR|Exercise Question|360 Videos

Similar Questions

Explore conceptually related problems

Number of complex numbers z satisfying z^(3)=bar(z) is

Number of complex numbers satisfying z^(3)=bar(z) is

Knowledge Check

  • The number of complex numbers satisfying (1 + i)z = i|z|

    A
    0
    B
    1
    C
    2
    D
    infinite
  • Let z_(1) = 2 + 3i and z_(2) = 3 + 4i be two points on the complex plane. Then the set of complex numbers z satisfying abs(z - z_(1))^(2) + (z - z_(2))^(2) = (z_(1) - z_(2))^(2) represents

    A
    a straight line
    B
    a point
    C
    a circle
    D
    a pair of straight lines
  • The complex number z satisfying the equation abs(z-1)=abs(z+1)=1 is

    A
    0
    B
    1+i
    C
    `-1+i`
    D
    `1-i`
  • Similar Questions

    Explore conceptually related problems

    The number of complex numbers z satisfying |z-2-i|=|z-8+i| and |z+3|=1 is

    The locus of a complex number z satisfying |z-(1+3i)|+|z+3-6i|=4

    Numbers of complex numbers z, such that abs(z)=1 and abs((z)/bar(z)+bar(z)/(z))=1 is

    The number of complex number z satisfying the equations |z|-4=|z-i|-|z+5i|=0 is

    The complex number z satisfying the equation |z-i|=|z+1|=1