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What mass of 95% pure CaCO3 will be requ...

What mass of `95%` pure `CaCO_3` will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction?
`(CaCO_3)_(s)+2HCl_(aq) to (CaCl_2)_(aq)+CO_2_(g)+2H_2O_(l)`
[Calculate upto second place of decimal point]

A

1.25 g

B

1.32 g

C

3.65 g

D

9.5 g

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Knowledge Check

  • The absolute enthalpy of neutralisation of the reaction MgO(s) + 2HCl(aq) to MgCl_(2)(aq) + H_(2)O(l) will be

    A
    less than -57.33 KJ `"mol"^(-1)`
    B
    `-57.33 KJ "mol"^(-1)`
    C
    greater than `-57.33 KJ "mol"^(-1)`
    D
    57.33 KJ `"mol"^(-1)`

  • The absolute enthalpy of neutralisation of the reaction: MgO(s) + 2HCl(aq) to MgCl_2(aq) + H_2O(l) will be

    A
    `-57.33 kJ "mol"^(-1)`
    B
    greater than `-57.33 kJ"mol"^(-1)`
    C
    less than `-57.33 kJ "mol"^(-1)`
    D
    `57.33 kJ "mol"^(-1)`