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For the reaction N(2)O(5) rarr 2NO(2) + ...

For the reaction `N_(2)O_(5) rarr 2NO_(2) + (1)/(2) O_(2)`, the rate of disappearance of `N_(2)O_(5)` is `6.25 xx 10^(-3) "mol L"^(-1) s^(-1)`. The rate of formation of `NO_(2)` and `O_(2)` will be respectively.

A

`6.25xx10^(-3)mol L^(-1)S^(-1) and 6.25xx10^(-3)mol L^(-1)S^(-1)`

B

`1.25xx10^(-3)mol L^(-1)S^(-1) and 3.125xx10^(-3)mol L^(-1)S^(-1)`and

C

`6.25xx10^(-3)mol L^(-1)S^(-1) and 3.125xx10^(-3)mol L^(-1)S^(-1)`and

D

`1.25xx10^(-3)mol L^(-1)S^(-1) and 6.25xx10^(-3)mol L^(-1)S^(-1)`and

Text Solution

Verified by Experts

The correct Answer is:
B

Given `-(-d[N_(2)O_(5)])/(dt)=6.25xx10^(-3)molL^(-1)S^(-1)`
For the reaction
`N_(2)O_(5) to 2NO_(2)+(1)/(2)O_(2)`
`(-d[N_(2)O_(5)])/(dt)=(1)/(2)(d[NO_(2)])/(dt)=(2d[O_(2)])/(dt)`
`therefore (d[NO_(2)])/(dt)=-(2d[N_(2)O_(5)])/(dt)=1.25xx10^(-2)molL^(-1)S^(-)`
`therefore (d[O_(2)])/(dt)=-(1)/(2)(d[N_(2)O_(5)])/(dt)`
`=3.12510^(-3)molL^(-1)S^(-1)`
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In a reaction, the concentration of a reatant (A) changes from 0.200 "mol litre"^(-1) to 0.150 "mol litre"^(-1) in 10 minutes. What is the average rate of reaction during this interval ? N_(2)O_(5)rarr2NO_(2)+_(1//2)O_(2) the rate of disappearance of N_(2)O_(5)"is" 6.5xx10^(-3)"mol" L^(-1)s^(-1) . Computer the rates of formation of NO_(2) and O_(2)

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Knowledge Check

  • For the reaction N_(2)O_(5) (g) to 2NO_(2) (g) + (1)/(2) O_(2) (g) the value of rate of disappearance of N_(2)O_(5) is given as 6.25 xx 10^(-3) mol L^(-1) S^(-1) . The rate of formation of NO_(2) and O_(2) is given respectively as

    A
    `1.25 xx 10^(-2)` mol `L^(-1) S^(-1)` and ` 6.25 xx 10^(-3)` mol `L^(-1) S^(-1)`
    B
    `6.25 xx 10^(-3)` mol `L^(-1) S^(-1)` and ` 6.25 xx 10^(-3)` mol `L^(-1) S^(-1)`
    C
    `1.25 xx 10^(-2)` mol `L^(-1) S^(-1)` and ` 3.125 xx 10^(-3)` mol `L^(-1) S^(-1)`
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    `6.25 xx 10^(-2)` mol `L^(-1) S^(-1)` and ` 3.125 xx 10^(-3)` mol `L^(-1) S^(-1)`
  • For the reaction, N_2O_5(g) rarr 2NO_2(g)+1//2O_2(g) , the value of rate of disappearance of N_2O_5 is given as 6.25xx10^(-3) "mol L"^(-1)s^(-1) . The rate of formation of NO_2 and O_2 is given respectively as

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    `6.25xx10^(-3)"mol L"^(-1)& 6.25xx10^(-3)"mol L"^(-1)s^(-1)`
    B
    `1.25xx10^(-2)"mol L"^(-1)& 3.125xx10^(-3)"mol L"^(-1)s^(-1)`
    C
    `6.25xx10^(-3)"mol L"^(-1) & 3.125xx10^(-3)"mol L"^(-1)s^(-1)`
    D
    `1.25xx10^(-2)"mol L"^(-1)& 6.25xx10^(-3)"mol L"^(-1)s^(-1)`
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    A
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    D
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