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The horizontal range and the maximum hei...

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

A

`theta= tan-1 (2)`

B

`theta=45^(@)`

C

`theta=tan^(-1)((1)/(4))`

D

`theta=tan^(-1)(4)`

Text Solution

Verified by Experts

The correct Answer is:
D
`tan theta=(4H)/(R )`
given H=R
`therefore theta=tan^(-1) (4)`
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