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Calculate the volume of 10 volume H(2)O ...

Calculate the volume of 10 volume `H_(2)O` solution that will react with 200 mL of 2N `KMnO_(4) ` in acidic medium.

Text Solution

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Normality of 10 volume `H_(2)O_(2)=("Volume strength")/(5.6)=(10)/(5.6) N`
Applying normality equation, `N_(1)V_(1)(H_(2)O_(2))=N_(2)V_(2)(KMnO_(4)`
`(10)/(5.6)xxV_(1)=2xx200` or `V_(1)=(2xx200xx5.6)/(10)=224` mL.
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Knowledge Check

  • The volume of 10 volume H_(2)O_(2) solution that decolourises 200 mL of 2 N KMnO_(4) solution in acidic medium is

    A
    112 mL
    B
    336 mL
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  • Hydrogen peroxide can be preapared by the action of dil. H_(2)SO_(4) or H_(3)PO_(4) on barium peroxide or by bubbling peroxide . On an industrial scale, it can be prepared by hydrolysis of peroxodisulphuric acid obtained by electrolysis of 50% H_(2)SO_(4) or an equimolar mixture of H_(2)SO_(4) and ammonium sulphate . The strength of H_(2)O_(2) solution can be expressed in a number of ways namely normality , molarity , percentage strength and volume strength . Volume strength refers to the volume of O_(2) produced at N.T.P. by decomposition of 1 mL of H_(2)O_(2) solution. H_(2)O_(2) acts as an oxidising as well as reducing agent both in acidic and basic media. The volume of 10 volume H_(2)O_(2) solution that decolourises 200 mL of 2N KMnO_(4) solution in acidic medium is :

    A
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    B
    336 mL
    C
    200 mL
    D
    224 mL

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