Why `N(CH_(3))_(3)` is pyramidal but `N(SiH_(3))_(3)` is planar ?

Explanation

To understand why \( N(CH_3)_3 \) is pyramidal while \( N(SiH_3)_3 \) is planar, we need to analyze the molecular geometry and hybridization of both compounds.

### Step-by-Step Solution:

**Step 1: Analyze \( N(CH_3)_3 \)**
- **Structure**: The nitrogen atom in \( N(CH_3)_3 \) is bonded to three methyl groups (CH₃) and has one lone pair of electrons.
- **Hybridization**: To determine the hybridization, we count the number of lone pairs and bonded pairs:
- Lone pairs = 1
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