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Write the state of hybridization of all ...

Write the state of hybridization of all the atoms in `CH_(2)=C=CH_(2)` and draw its orbital structure. Do the two atoms on `C_(1)` lie in the same plane in which hydrogens on `C_(3)` lie. Explain.

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To determine the hybridization of all the atoms in the compound \( CH_2=C=CH_2 \) (propene), we will analyze the structure step by step. ### Step 1: Identify the structure The compound \( CH_2=C=CH_2 \) consists of three carbon atoms connected by double bonds. The structure can be represented as follows: ``` H H \ / ...
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Write the state of hybridisation of all the carbon atoms in CH_2 = C = CH_2 .

For a given molecule : CF_(2)=C=C=C=CH-CH_(3) ltbrrgt find the maximum number of atoms which may lie in the same plane.

Knowledge Check

  • The hybrid state of C atom in C_(2)H_(2) is same as that of carbon in

    A
    ` C_(2)H_(6) `
    B
    `CO_(2)`
    C
    Benzene
    D
    C(Diamond)
  • Hybridization of C_(2) and C_(3) of H_(3)C-CH=C=CH-CH_(3) are:

    A
    `sp,sp`
    B
    `sp,sp^(3)`
    C
    `sp^(2),sp^(2)`
    D
    `sp^(2),sp`
  • Which of the following species has the same hybridization as C in CH_(2)=CH_(2) ?

    A
    `CO_(3)^(2-)`
    B
    `XeF_(4)`
    C
    `PCl_(3)`
    D
    `I_(3)^(-)`
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