Why electron cannot exist inside the nucleus according to Heisenberg's uncertainty principle?

Explanation

Diameter of the atomic nucleus is of the order of `10^(-15) m`
`:.` The maximum uncertainity in the position of electron is `10^(-15)` m
Mass of electron `= 9.1xx 10^(-31) kg`
Now,
`Deltax .Deltap = ( h)/( 4pi)`
`Deltax xx ( mDeltav )= ( h)/( 4pi)`
`Deltav = ( h)/( 4pi) xx (1 )/(Deltax-m)= ( 6.26 xx 10^(-34))/( 4 xx ((22)/( 7)))xx ( 1)/( 10^(-15) xx 9.1xx 10^(-31))`
`Deltav = 5.80 xx 10^(10) ms^(-1)`
This value is much higher than the velocity of light and hence,it is not possible.