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Sholve the simultasneous vector equation...

Sholve the simultasneous vector equations for `vecx aedn vecy: vecx+veccxxvecy=veca and vecy+veccxxvecx=vecb, vec!=0

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The correct Answer is:
`vecx=(veca+vecbxxvec c+(vec c.veca)vec c)/(1+c^(2))`
`vecy=(vecb+vecaxxvec c+(vec c.vecb)vec c)/(1+c^(2))`
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