Pyrolustie on heating with KOH in the presence of air gives dark green compound (A).The solution of (A) on treatment with `H_(2)SO_(4)` gives a purple coloured compound (B) which gives the following reactions `:`
(i) Alkaline solution of B on reaction with KI changes it into compound (C ).
(ii) The color of the compound (B) disappears on treatment with acidic soluiont of `FeSO_(4)`.
(iii) On reaction with conc. `H_(2)SO_(4)` compound (B) gives another compound (D) which can decompose to produce compound (E ) along with oxygen gas. Identify compounds (A) to (E ) and write balanced chemical equation involved in each case.

Explanation

To solve the problem, we will identify the compounds A to E based on the given reactions and their characteristics.

### Step 1: Identify Compound A
**Given:** Pyrolusite (MnO₂) is heated with KOH in the presence of air.
**Reaction:**
\[ \text{MnO}_2 + 4 \text{KOH} + \text{O}_2 \rightarrow 2 \text{K}_2\text{MnO}_4 + 2 \text{H}_2\text{O} \]
**Conclusion:** Compound A is Potassium Manganate, \( \text{K}_2\text{MnO}_4 \).

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