If `tan(alpha+beta)=ntan(alpha-beta)` then show that `(n+1)sin2beta=(n-1)sin2alpha`

If tan theta=(tan alpha+tan beta)/(1+tan alpha tan beta) then show that sin2 theta=(sin2 alpha+sin2 beta)/(1+sin2 alpha sin2 beta)

If tan theta = ( tan alpha + tan beta)/(1 + tan alpha tan beta),"show that " sin 2 theta =(sin 2 alpha + sin 2 beta)/(1+sin 2 alpha sin 2 beta)

If tan theta = ( tan alpha - tan beta)/(1-tan alpha tan beta),"show that", sin 2 theta=(sin 2 alpha- sin 2 beta)/(1- sin2 alpha sin 2 beta).

If sin (alpha+beta)=1, sin (alpha-beta)=1/2 , then tan (alpha+ 2beta). tan (2 alpha+beta) is equal to :

If n tan alpha=(n+1)tan beta then show that tan(alpha-beta)=(sin2 beta)/(2n+1-cos2 beta)

If sin (alpha+beta ) =1 , sin (alpha-beta ) =1//2 " then " tan (alpha +2beta ) tan(2alpha+beta ) =

If sin(alpha+beta)=1,sin(alpha-beta)=(1)/(2) then tan(alpha+2 beta)tan(2 alpha+beta)=

If sin(alpha + beta) = 1 , sin(alpha - beta) = 1/2 , then : tan(alpha + 2beta)tan(2alpha + beta) is equal to :

if tan alpha=2tan beta show that (sin(alpha+beta))/(sin(alpha-beta))=3

If sin (alpha + beta)=1, sin (alpha- beta)= (1)/(2) , then tan (alpha + 2beta) tan (2alpha + beta) =