In a `DeltaABC`, prove that : `tanA+tanB+tanC= tanA tanB tanC`

tanA +tanB + tanC = tanA tanB tanC if

In DeltaABC , prove that: tanA/2tanB/2+tanB/2tanC/2+tanC/2tanA/2=1

In DeltaABC , tanA+tanB+tanC=tanAtanBtanC

In DeltaABC , prove that: s^(2).tanA/2tanB/2tanC/2=Delta

Prove that: (tanA + tanB)/(cotA+cotB)=tanAtanB

In DeltaABC, if tanA+tanB+tanC=6 and tanA.tanB=2 then tanC= . .

If A+B+C=npi (n being an integer). Show that tanA+tanB+tanC=tanA tanB tanC .

If A+B+C= pi/2 , show that : tanA tanB + tanB tanC + tanC tanA=1

If A+B+C=pi , show that : tanA+tanB+tanC=tanA.tanB.tanC Hence. Deduce the value of : cotA.cotB+cotB.tanC+cotC.cotA

If tanA+tanB+tanC=tanA.tanB.tanC , then-