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In a DeltaABC, prove that : tanA+tanB+ta...

In a `DeltaABC`, prove that : `tanA+tanB+tanC= tanA tanB tanC`

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In DeltaABC , prove that: tanA/2tanB/2+tanB/2tanC/2+tanC/2tanA/2=1

In DeltaABC , tanA+tanB+tanC=tanAtanBtanC

Knowledge Check

  • tanA +tanB + tanC = tanA tanB tanC if

    A
    `A + B + C= pi`
    B
    `A + B + C= 2pi`
    C
    `A + B + C= npi`
    D
    `A + B + C= pi//2`

  • In DeltaABC, if tanA+tanB+tanC=6 and tanA.tanB=2 then tanC= . .

    A
    3
    B
    4
    C
    1
    D
    2

  • If tanA+tanB+tanC=tanA.tanB.tanC , then-

    A
    A,B,C must be angles of a triangle
    B
    the sum of any two of A,B,C is equal to the third
    C
    A+B+C must be n integral multiple of `pi`
    D
    None of these

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    In DeltaABC , prove that: s^(2).tanA/2tanB/2tanC/2=Delta

    Prove that: (tanA + tanB)/(cotA+cotB)=tanAtanB

    If A+B+C=npi (n being an integer). Show that tanA+tanB+tanC=tanA tanB tanC .

    If A+B+C= pi/2 , show that : tanA tanB + tanB tanC + tanC tanA=1

    If A+B+C=pi , show that : tanA+tanB+tanC=tanA.tanB.tanC Hence. Deduce the value of : cotA.cotB+cotB.tanC+cotC.cotA

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