-If `f(x)` is a quadratic expression such that `f(-2) = f(2)= 0` and `f(1) =6` then `Lim_(x->0) (sqrt(f(x))-2sqrt2)/(ln(cosx))` is equal to

Let f(x) be a quadratic expression such that f(0) +f(1) =0 . If f(-2) =0 then

If f(x) is a quadratic function such that f(0)=3,f(1)=6 and f(2)=11 , then: f(x)=

If f(x)=0 is a quadratic equation such that f(-pi)=f(pi)=0 and f(pi/2)=-(3pi^2)/4, then lim_(x->-pi)(f(x))/("sin"(sinx) is equal to

If f(4)=4,f'(4)=1, then lim_(x in4) (2-sqrt(f(x)))/(2-sqrt(x)) is equal to

If f(1) = 1, f'(1) = 2 then lim_(x to 1 ) (sqrt(f(x))-1)/(sqrt(x)-1) is equal to -

If f(1)=1,f'(1)=2 then lim_(x rarr1)(sqrt(f(x)-1))/(sqrt(x)-1) is equal to

If f(x)=0 is a quadratic equation such that f(-pi)=f(pi)=0 and f((pi)/(2))=-(3pi^(2))/(4) , then lim_(xto -pi^+) (f(x))/(sin(sinx)) is equal to

If f(x)=0 is a quadratic equation such that f(-pi)=f(pi)=0 and f((pi)/(2))=-(3pi^(2))/(4) , then lim_(xto -pi^+) (f(x))/(sin(sinx)) is equal to

If f(1)=3 and f'(1)=6 , then lim_(x rarr0)(sqrt(1-x)))/(f(1))

If f(x) is a quadratic polynomial such that f(0) = 2, f(0) = -3 and f'(0) = 4 , then int_(-1)^(1) f(x) dx equals: