250 mL of 0.1 N solution of HCI contains

Options

A. 0.25 g mole of HCI
B. 0.025 g mole of HCI
C. 9.12 g moles of HCI
D. 0.912 g moles of HCI

Answer

B

Explanation

Normality = molarirty ` xx ` charge on cation or anion
250 mL of 0.1 N HCI = 250 mL of 0.1 M HCI M
(0.1)/4` g mol
= 0.025 g moles of HCI