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10g of a mixture of BaO and CaO requires...

`10g` of a mixture of `BaO` and `CaO` requires `100cm^(3)` of `2.5m HCl` of react competely. The percentage of calcium oxide in the mixture is approximately
(given, molar mass of `BaO=153`)

A

52.6

B

55.1

C

44.9

D

47.9

Text Solution

Verified by Experts

The correct Answer is:
A
Let mass of `CaO=xg`
`:.` Mass of `BaO=(10-x)g`
Again equivalent mass of `BaO`
`=("molar mass")/2=153/2=76.5`
`:.` Number of moles of `BaO`
`=(10-x)/76.5`
and equivalent mass of `CaO`
`=56/2=28`
`:.` Number of moles of `CaO=x/28`
from molarity
`=("moles of solute")/("volume of solution"("in"L))`
`2.5=("moles of solute")/(100/1000)`
`:.`Moles of solute `=(2.5xx100)/1000=0.25`
`:.` For complete neutralisation (reaction), moles of `BaO` and `CaO=` moles of HCl (solute)
`:.x/28+(10-x)/76.5=0.25`ltbRgt or `76.5+28(10-x)`
`=0.25xx28xx76.5`
or `48.5x=255.5`
or `x=255.5/48.5=5.26`
`:.%` of `CaO=5.26/10xx100=52.6%`
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Knowledge Check

  • 10 g of a mixture of BaO and CaO requires 100 cm^(3) of 2.5M HCl to react completely. The percentage of calcium oxide in the mixture is approximately (Given molar mass of BaO = 153, CaO = 56)

    A
    52.6
    B
    55.1
    C
    44.9
    D
    47.4

  • 10.0 g of a mixture of BaO and CaO require 100 mL of 2.50 M HCl to react with it completely. Amount of BaO in the mixture is (At mass Ca = 40, Ba = 137, O = 16)

    A
    `47.3%`
    B
    `43.7%`
    C
    `37.4%`
    D
    `74.37%`

  • A mixture containing equimolar amounts of Ca(OH)_(2) and Al(OH)_(3) requires 0.5 L of 4.0 M HCl to react with it completely. Moles of the mixture are :

    A
    `0.04`
    B
    `0.4`
    C
    `0.8`
    D
    0
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