A vessel containing one of mole of a monatomic ideal gas `(molecular weight = 20 g mol_^(1))` is moving on a floor at a speed of `50 m s^(-1)` The vessel is stopped suddenly. Assuming that the mechanical energy lost has gone into the internal energy of the gas , find the rise in its temperature .

Explanation

`N = 1mol e`,
`W=20 g//mol e`, `V=50 m//s`
K.E. of the vessel = internal energy of the gas
`K.E. = 1//2 mV^2`
`=1//2 xx 20 xx 10 ^(-3) xx 50xx 50`
`=25 J`.
So, `25 =3//2 n R(DeltaT)`
implies `25=1xx3//2 xx8.31xx DeltaT`
implies `DeltaT= 50/(3xx8.3) = 2K`.