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The complex [NiCl(4)]^(2-) has tetrahedr...

The complex `[NiCl_(4)]^(2-)` has tetrahedral geometry while `[Ni(CN)_(4)]^(2-)` has square planar geometry. Explain.

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To explain the difference in geometries of the complexes \([NiCl_4]^{2-}\) and \([Ni(CN)_4]^{2-}\), we will analyze the oxidation state of nickel, its electronic configuration, the nature of the ligands, and the resulting hybridization. ### Step-by-Step Solution: 1. **Determine the Oxidation State of Nickel:** - For both complexes, we can determine the oxidation state of nickel (Ni). - In \([NiCl_4]^{2-}\): Let the oxidation state of Ni be \(x\). \[ ...
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[Ni(CO)_(4)] possess tetrahedral geometry while [Pt(NH_(3))_(2)Cl_(2)] has square planar geometry. Explain.

Account for the fact that [Ni(CO)_(4)] has tetrahedral geometry whereas [Ni(CN)_(4)]^(2-) has square planar geometry.

Knowledge Check

  • Which has square planar geometry

    A
    `[Pt(NH_(3))_(2)Cl_(2)]`
    B
    `[Ni(CN)_(4)]^(2-)`
    C
    Both (a) and (b)
    D
    None of these

  • [NiCl_(4)]^(2-) has geometry

    A
    square planar
    B
    tetrahedral
    C
    square bipyramidal
    D
    trigonal bipyramidal

  • The complex having square planar geometry is

    A
    `[Ni(CO)_(4)]`
    B
    `[MnCl_(4)]^(2-)`
    C
    `[CuCl_(4)]^(2-)`
    D
    `[Cu(NH_(3))_(4)]^(2+)`

    • Similar Questions

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    Why is [NiCl_(4)]^(2-) paramagnetic while [Ni(CN)_(4)]^(2-) is diamagnetic ?

    How will you account for the following : (i) [Fe(CN)_6]^(-) is weakly paramagnetic while [Ni(CN)_4]^(2+) diamagnetic. (ii) [Ni(CO)_4] possess tetrahedral geometry while [Ni(CN)_4]^(2-) is square planar.

    Explain the following giving reasons (a) [NiCI_(4)]^(2-) is tetrahedral and paramagnetic whereas [Ni(CN)_(4)]^(2-) is square plannar and dimagnetic (b) [Fe(H_(2)O)_(6)]^(3+) ion is more paramagnetic than [Fe(CN)_(6)]^(3-) ion (c ) Ni(CO)_(4) is tetrahedral while [Ni(CN)_(4)]^(2-) ion is square planar (d) [Co(F_(6))]^(3-) is a high spin complex whereas [Co(CN)_(6)]^(3-) ion is a low spin complex .

    The number of unpaired electrons in [Pt(CN)_(4)]^(2-) ion having square planar geometry At.No.of Pt=78) is

    Which of the following has a square planar geometry? .

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