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The charge on a proton is +1.6 X 10(-19)...

The charge on a proton is `+1.6 X 10(-19) C` and that on an
. electron is `-1.6 X 10 (-19)C.` Does it mean that the electron
. has a charge `3.2 X 10(-19) c` less than the charge of a
. proton?

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The charges on an object is given by Q = ne, here n is number of electrons and e is electronic charge (-1.6 xx 10^(-19) C) . If an object has charge -5 xx 10^(-19) C , what should be number of excess electron on it?

Knowledge Check

  • The charge on the electron is 1.6 xx 10^(-19) C . The order of magnitude is

    A
    `10^(19)C`
    B
    `10^(18)m`
    C
    `10^(-18)C`
    D
    `10^(-19)C`
  • The charge of an electron is 1.6 xx 10^(-19)C what will be the value of charge on Na^(+) ion.

    A
    `1.6 xx 10^(-19)C`
    B
    `3.2 xx 10^(-19)C`
    C
    `2.4 xx 10^(-19)C`
    D
    `10 xx 1.6'10^(-19)C`
  • The charge of an electron is -1.6 xx10^(-19) C. The value of free charge on Li^+ ion will be

    A
    `3.6xx10^(-19)` C
    B
    `1xx10^(-19)` C
    C
    `1.6xx10^(-19)` C
    D
    `2.6xx10^(-19)` C
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