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Two charged particles are placed at a distance 1.0 cm apart. What is the minimum possible magnitude of the electric force acting o each charge?

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To find the minimum possible magnitude of the electric force acting on each charge when two charged particles are placed at a distance of 1.0 cm apart, we can use Coulomb's law. Here’s a step-by-step solution: ### Step 1: Understand Coulomb's Law Coulomb's law states that the electric force \( F \) between two point charges \( q_1 \) and \( q_2 \) separated by a distance \( r \) is given by the formula: \[ F = k \frac{|q_1 q_2|}{r^2} \] where: ...
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HC VERMA-ELECTRIC FIELD AND POTENTIAL-Exercises
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  2. Suppose the second charge in the previous problem is -1.0 xx 10^(-6) C...

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  3. Two charged particles are placed at a distance 1.0 cm apart. What is t...

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  15. Ten positively charged particles are kept fixed on the x-axis at point...

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  16. Two charged particles having charge 2.0xx 10^(-8)C each are joined by ...

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  17. Two indentical balls, each having a charge of 2.00xx10^(-7) C and a ma...

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  18. Two identical pith balls are charged by rubbing against each other. T...

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  19. Two small spheres, each having a mass of 20 g, are suspended form a co...

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