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A battery of emf 2.0 volts and internal ...

A battery of emf 2.0 volts and internal resistance `0.10(Omega)`is being charged with a current of 5.0A. What is the potential difference between the terminals of the battery?

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To find the potential difference between the terminals of the battery while it is being charged, we can use the formula that relates the electromotive force (EMF), internal resistance, and the current flowing through the battery. ### Step-by-Step Solution: 1. **Identify the given values:** - EMF of the battery (E) = 2.0 volts - Internal resistance of the battery (r) = 0.10 ohms - Charging current (I) = 5.0 A ...
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