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Find the ratio of Li^(++) ions in its gr...

Find the ratio of `Li^(++)` ions in its ground state assuming Bohr 's model to be vaild

Text Solution

Verified by Experts

For hydrogen like ionthe radius of the nth orbit is
`a_(n)= (n^(2)a_(0))/(2)`
For `Li^(++) ,Z= 3` and in ground state `n = 1` , The radius is
`a_(1) = (53pm)/(3) = 18 pm`
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(a) Find the radius of Li(++) ions in its grounds state assuming Bohr's model to be valid. (b) Find the maximum angular speed of the electron of a hydrogen atom in a stationary orbit. (c ) Average lifetime of a H atom excited to n=2 state is 10^(-8) sec. Find the number of revolutions made by the electron on the average before it jumps to the ground state. (d) Calculate the magnetic dipole moment corresponding to the motion of the electron in the ground state of a hydrogen atom. (e) Using the known values for hydrogen atom, calculate : (i) radius of third orbit for Li^(+2) (ii) speed of electron in fourth orbit for He^(+)

The amount of energy required to remove electron from a Li^(2+) ion in its ground state is how many times greater than the amount of energy needed to remove the electron from an H artom in its ground state?

Knowledge Check

  • Find the radius of Li^(++) ions in its ground state assuming Bohr's model to be valid.

    A
    `12xx10^(-10)m`
    B
    `12xx10^(-12)m`
    C
    `16xx10^(-10)m`
    D
    `18xx10^(-12)m`.

  • Taking the Bohr radius as r_(0)=53 pm, the radius of Li^( + +) ion in its ground state, on the basis of Bohrs model, will be a about

    A
    53pm
    B
    27pm
    C
    18pm
    D
    13pm

  • Taking the Bohr radius a_(0) = 53 pm, the radius of Li^(++) ion in its gnround state, on the basis of Bohr's model, will be about.

    A
    53 pm
    B
    27 pm
    C
    18 pm
    D
    13 pm

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    The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.60 xx 10^(-16) second. The time period of revolution of the electron in its first excited state in a Li^(++) ion is:

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