Gravitational Potential At A Point Due To The Earth

If V is the gravitational potential on the surface of the earth, then what is its value at the centre of the earth ?

How is gravitational potential on the surface of earth, at a given point, related with acceleration due to gravity g? Take radius of earth = R.

The gravitational potential at a point above the surface of earth is -5.12times10^(7)J//kg and the acceleration due to gravity at that point is 6.4m//s^(2) .Assume that the mean radius of earth to be 6400km" .The height of this point above the earth's surface is :

The gravitational potential at some point above the surface of the earth is -4.32 xx 10^(7) J//kg and acceleration due to gravity at that point is 5.4 m//s^(2) . If the mean radius of earth is 6.37 xx 10^(6)m , then find the height of this point from the earth's surface.

Gravitational potential at a height R from the surface of the earth will be [Take M = mass of the earth, R = radius of the earth]

Gravitational Potential|Gravitational Potential Due To Point Mass|Gravitational Potential Due To Spheres

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A satellite of mass 50 kg moves from a point where the gravitational potential due to the Earth is -20MNkg^(-1) to another point where the gravitational potential is -60MJkg^(-1) .During the change of position, it has moved

Assertion : If gravitational potential at some point is zero, then gravitational field strength at that point will also be zero. Reason : Except at infinity gravitational potential due to a system of point masses at some finite distance can't be zero.