Triangles on the same base and between the same parallel are equal in area.
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In `ABFD`
`DF||AB` and `BF||AD`
Thus, both pair of opposite sides are parallel.
Hence, `ABFD` id a parallelogram.
Similarly, we can prove that `ABCE` is a parallelogram with same base and between two parallels `AB` and `EF`.
`ar(ABFD)=ar(ABCE)`
In parallelogram `ABFD`,
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