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A particle performing uniform circular motion has angular frequency is doubled & its kinetic energy halved, then the new angular momentum is

A

`(L)/(4)`

B

2L

C

4L

D

`(L)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
(a)K.E.(1)/(2)Iomega^2, but Iomega rArr I (L)/(omega)`
`:. K.E. =(1)/(2) (L)/(omega)xx omega^2 = (1)/(2)L omega`
`:. (K.E)/(K.E) = (Lxxomega)/(L'xxomega') rArr ((K.E)/(K.E)/(2)) = (Lxxomega)/(L'xx2omega) :. L'= (L)/(4)
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Knowledge Check

  • A body performing uniform circular motion has

    A
    constant velocity
    B
    constant acceleration
    C
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