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An inorganic substance has the following...

An inorganic substance has the following composition:
`N = 35% H = 5%, O = 60 %`
On being heated, it yielded a gaseous compound containing `N = 63.63%` and `O = 36.37%`. Suggest a formula for each substance and equation for the chemical change.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
`{:("Element", "Moles", "Least ratio", "Whole no. ratio"),(N, (15)/(14) = 2.5, (2.5)/(2.5) = 1, 2),(H,(5)/(1) = 5, (5)/(2.5) = 2, 4),(O,(60)/(16) = 3.75, (3.75)/(2.5) = 1.5,3):}`
Empirical formula `N_(2) H_(4) O_(3) = NH_(4) NO_(3)`
`NH_(4) NO_(3) overset(Delta)rarr N_(2) O + 2H_(2) O`
b. Empirical formula of the gaseous product:
`{:("Element", "Moles", "Least ratio"),(N, (63.63)/(14) = 4.545, (4.545)/(2.273) = 1.99 ~~ 2),(O, (36.37)/(16) = 2.273, (2.273)/(2.273) = 1):}`
Empirical formula `= N_(2) O`
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Knowledge Check

  • An organic compound containing C = 38.8%, H = 16% and n = 45.2% . Empirical formula of the compound is

    A
    `CH_(3)NH_(2)`
    B
    `CH_(3)CN`
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    `C_(2)H_(5)CN`
    D
    `CH_(2)(NH)_(2)`

  • An organic compound contains C=40% , H=13.33% and N=46.67% . Its empirical formula would be

    A
    `CHN`
    B
    `C_(2)H_(2)N`
    C
    `CH_(3)N`
    D
    `C_(3)H_(2)N`

  • An organic compound contains C = 40%, H = 13.33% , and N = 46.67% . Its empirical formula will be

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    `CHN`
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    C
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    D
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