`10 g` of `CaCO_(3)` contains

Options

A. 10 moles of `CaCO_(3)`
B. `0.1 g` atom of `Ca`
C. `6 xx 10^(23)` atoms of `Ca`
D. 0.1 of equivalent of `Ca`

Explanation

To find the number of moles in 10 g of calcium carbonate (CaCO₃), we can follow these steps:

### Step 1: Write down the formula for calculating moles.
The formula to calculate the number of moles (n) is:
\[ n = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]

### Step 2: Calculate the molar mass of calcium carbonate (CaCO₃).
To find the molar mass, we need to sum the atomic masses of all the atoms in the compound:
- Atomic mass of Calcium (Ca) = 40 g/mol
- Atomic mass of Carbon (C) = 12 g/mol
- Atomic mass of Oxygen (O) = 16 g/mol

Since there are three oxygen atoms in CaCO₃, we calculate the total mass as follows:
\[ \text{Molar mass of CaCO₃} = \text{mass of Ca} + \text{mass of C} + 3 \times \text{mass of O} \]
\[ \text{Molar mass of CaCO₃} = 40 + 12 + (3 \times 16) \]
\[ \text{Molar mass of CaCO₃} = 40 + 12 + 48 \]
\[ \text{Molar mass of CaCO₃} = 100 \text{ g/mol} \]

### Step 3: Substitute the values into the moles formula.
Now, we can substitute the given mass of CaCO₃ and its molar mass into the formula:
\[ n = \frac{10 \text{ g}}{100 \text{ g/mol}} \]

### Step 4: Calculate the number of moles.
\[ n = 0.1 \text{ moles} \]

### Final Answer:
10 g of CaCO₃ contains **0.1 moles**.

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