The total number of electrons present in...

The total number of electrons present in `18 mL` of water is ……

Text Solution

Verified by Experts

The correct Answer is:

A, B, C, D

The total numbe of electrons present in `18 mL` of water is `6.023 xx 10^(24)`.
Number of electron in one molecules of `H_(2) O` is `2 + 8 = 10`
Denisty = 1
`18 mL` means `18 g`
Moles `= (18)/(18) = 1`
Moles `= 6.023 xx 10^(23)`
Electrons `= 6.023 xx 10^(23) xx 10 = 6.023 xx 10^(24)`

Topper's Solved these Questions

SOME BASIC CONCEPTS AND MOLE CONCEPT
CENGAGE CHEMISTRY|Exercise Archives Subjective|11 Videos
SOME BASIC CONCEPTS AND MOLE CONCEPT
CENGAGE CHEMISTRY|Exercise Archives Integer|4 Videos
S-BLOCK GROUP 2 - ALKALINE EARTH METALS
CENGAGE CHEMISTRY|Exercise Ex 5.1 Objective|2 Videos
STATES OF MATTER
CENGAGE CHEMISTRY|Exercise Exercises (Ture False)|25 Videos

The total number of electrons present in 18 mL of water (density of water is 1 g mL^(-1) ) is

`6.02 xx 10^(23)`

`6.02 xx 10^(22)`

`6.02 xx 10^(24)`

`6.02 xx 10^(25)`

The total number of electrons present in 18ml of water ( density of water is 1g/ml)

`6.02xx10^(20)`

`6.02xx10^(23)`

`6.02xx10^(24)`

`6.02xx10^(26)`

Total number of electrons present in 18 mL of water (density of water is 1 g/mL) is

`6.02xx10^(23)`

`6.02xx10^(22)`

`6.02xx10^(24)`

`6.02xx10^(25)`