A particle is moving in x-y plane with its x and y co-ordinates varying with time as, `x=2t and y=10t-16t^2.` Find trajectory of the particle.
A particle is moving in x-y plane with its x and y co-ordinates varying with time as, `x=2t and y=10t-16t^2.` Find trajectory of the particle.
Text Solution
Verified by Experts
The correct Answer is:
A
Given, `x=2t`
rArr `t=x/2`
Now, `y=10t-16t^2`
Substituting value of t in this equation we have,
`y=10(x/2)-16(x)^2`
or `y=5x-4x^2`
This is the required equation of trajectory of the particle. This is a quadratic equation. Hence,
the path of the particle is a parabola.
rArr `t=x/2`
Now, `y=10t-16t^2`
Substituting value of t in this equation we have,
`y=10(x/2)-16(x)^2`
or `y=5x-4x^2`
This is the required equation of trajectory of the particle. This is a quadratic equation. Hence,
the path of the particle is a parabola.
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Knowledge Check
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D
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