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Two block of masses m(1) and m(2) connec...

Two block of masses `m_(1)` and `m_(2)` connected by a light spring rest on a horixontal plane. The cofficient of friction between the block and the surface is equal to `mu`. What minimum constant force has to be applied in the horizontal direction to the block of mass `m_(1)` in order to shift the other block?

Text Solution

Verified by Experts

The correct Answer is:
A, B

`(F-mum_(1)g)x_(m) =1/2kx_(m)^(2)`
or `kx_(m) =2(F-mu_(1)m_(1)g)`
Second block will shift if `kx_(m)gemum_(2)g`
`:. 2(F-mum_(1)g)gtmum_(2)g`
or `F gt(m_(1) + m^(2)/2)mug`.
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Two blocks of masses M_(1) and M_(2) connected by a light spring rest on a horizontal plane . The coefficient of friction between the blocks and the surface is equal to mu . The minimum constant force that has to be applied in the horizontal direction to the block of mass M_(1) in order to shift the other block is (M_(1) + (M_(2))/(alpha)) mu g , then alpha is :

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Knowledge Check

  • Two bars of masses m_(1) and m_(2) connected by a non - deformed light spring rest on a horizontal plane. The coefficient of friction between the bars and the surface is equal to mu . What minimum constant force has to be appled in the horizontal direction to the bar of mass m_(1) in order to shift the other bar?

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    B
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  • Two blocks of masses m_(1) = 1 kg and m_(2) = 2 kg are connected by a non-deformend light spring. They are lying on a rough horizontal surface. The coefficient of friction between the blocks and the surface is 0.4. What minimum constant force F has to be applied in horizontal direction to the block of mass m_(1) in order to shift the other block? (g = 10 m//s^(2))

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  • Two blocks of masses m_(1) and m_(2) are connected by a spring having spring constant K. Initially , the spring is at its natural length. The coefficient of friction between the blocks and the surface is mu . What minimum constant force has to be applied in the horizontal direction to the block of mass m_(1) , in order to shift the other block ?

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